Optimal. Leaf size=91 \[ \frac {A+B}{8 d (a-a \sin (c+d x))}-\frac {a (A-B)}{8 d (a \sin (c+d x)+a)^2}+\frac {(3 A+B) \tanh ^{-1}(\sin (c+d x))}{8 a d}-\frac {A}{4 d (a \sin (c+d x)+a)} \]
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Rubi [A] time = 0.14, antiderivative size = 91, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 31, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.097, Rules used = {2836, 77, 206} \[ \frac {A+B}{8 d (a-a \sin (c+d x))}-\frac {a (A-B)}{8 d (a \sin (c+d x)+a)^2}+\frac {(3 A+B) \tanh ^{-1}(\sin (c+d x))}{8 a d}-\frac {A}{4 d (a \sin (c+d x)+a)} \]
Antiderivative was successfully verified.
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Rule 77
Rule 206
Rule 2836
Rubi steps
\begin {align*} \int \frac {\sec ^3(c+d x) (A+B \sin (c+d x))}{a+a \sin (c+d x)} \, dx &=\frac {a^3 \operatorname {Subst}\left (\int \frac {A+\frac {B x}{a}}{(a-x)^2 (a+x)^3} \, dx,x,a \sin (c+d x)\right )}{d}\\ &=\frac {a^3 \operatorname {Subst}\left (\int \left (\frac {A+B}{8 a^3 (a-x)^2}+\frac {A-B}{4 a^2 (a+x)^3}+\frac {A}{4 a^3 (a+x)^2}+\frac {3 A+B}{8 a^3 \left (a^2-x^2\right )}\right ) \, dx,x,a \sin (c+d x)\right )}{d}\\ &=\frac {A+B}{8 d (a-a \sin (c+d x))}-\frac {a (A-B)}{8 d (a+a \sin (c+d x))^2}-\frac {A}{4 d (a+a \sin (c+d x))}+\frac {(3 A+B) \operatorname {Subst}\left (\int \frac {1}{a^2-x^2} \, dx,x,a \sin (c+d x)\right )}{8 d}\\ &=\frac {(3 A+B) \tanh ^{-1}(\sin (c+d x))}{8 a d}+\frac {A+B}{8 d (a-a \sin (c+d x))}-\frac {a (A-B)}{8 d (a+a \sin (c+d x))^2}-\frac {A}{4 d (a+a \sin (c+d x))}\\ \end {align*}
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Mathematica [A] time = 0.29, size = 75, normalized size = 0.82 \[ \frac {\frac {A+B}{a-a \sin (c+d x)}+\frac {B-A}{a (\sin (c+d x)+1)^2}+\frac {(3 A+B) \tanh ^{-1}(\sin (c+d x))}{a}-\frac {2 A}{a \sin (c+d x)+a}}{8 d} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.61, size = 161, normalized size = 1.77 \[ -\frac {2 \, {\left (3 \, A + B\right )} \cos \left (d x + c\right )^{2} - {\left ({\left (3 \, A + B\right )} \cos \left (d x + c\right )^{2} \sin \left (d x + c\right ) + {\left (3 \, A + B\right )} \cos \left (d x + c\right )^{2}\right )} \log \left (\sin \left (d x + c\right ) + 1\right ) + {\left ({\left (3 \, A + B\right )} \cos \left (d x + c\right )^{2} \sin \left (d x + c\right ) + {\left (3 \, A + B\right )} \cos \left (d x + c\right )^{2}\right )} \log \left (-\sin \left (d x + c\right ) + 1\right ) - 2 \, {\left (3 \, A + B\right )} \sin \left (d x + c\right ) - 2 \, A - 6 \, B}{16 \, {\left (a d \cos \left (d x + c\right )^{2} \sin \left (d x + c\right ) + a d \cos \left (d x + c\right )^{2}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.23, size = 147, normalized size = 1.62 \[ \frac {\frac {2 \, {\left (3 \, A + B\right )} \log \left ({\left | \sin \left (d x + c\right ) + 1 \right |}\right )}{a} - \frac {2 \, {\left (3 \, A + B\right )} \log \left ({\left | \sin \left (d x + c\right ) - 1 \right |}\right )}{a} + \frac {2 \, {\left (3 \, A \sin \left (d x + c\right ) + B \sin \left (d x + c\right ) - 5 \, A - 3 \, B\right )}}{a {\left (\sin \left (d x + c\right ) - 1\right )}} - \frac {9 \, A \sin \left (d x + c\right )^{2} + 3 \, B \sin \left (d x + c\right )^{2} + 26 \, A \sin \left (d x + c\right ) + 6 \, B \sin \left (d x + c\right ) + 21 \, A - B}{a {\left (\sin \left (d x + c\right ) + 1\right )}^{2}}}{32 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.56, size = 169, normalized size = 1.86 \[ -\frac {3 \ln \left (\sin \left (d x +c \right )-1\right ) A}{16 a d}-\frac {\ln \left (\sin \left (d x +c \right )-1\right ) B}{16 a d}-\frac {A}{8 a d \left (\sin \left (d x +c \right )-1\right )}-\frac {B}{8 a d \left (\sin \left (d x +c \right )-1\right )}-\frac {A}{4 a d \left (1+\sin \left (d x +c \right )\right )}-\frac {A}{8 a d \left (1+\sin \left (d x +c \right )\right )^{2}}+\frac {B}{8 a d \left (1+\sin \left (d x +c \right )\right )^{2}}+\frac {3 \ln \left (1+\sin \left (d x +c \right )\right ) A}{16 d a}+\frac {\ln \left (1+\sin \left (d x +c \right )\right ) B}{16 d a} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.33, size = 113, normalized size = 1.24 \[ \frac {\frac {{\left (3 \, A + B\right )} \log \left (\sin \left (d x + c\right ) + 1\right )}{a} - \frac {{\left (3 \, A + B\right )} \log \left (\sin \left (d x + c\right ) - 1\right )}{a} - \frac {2 \, {\left ({\left (3 \, A + B\right )} \sin \left (d x + c\right )^{2} + {\left (3 \, A + B\right )} \sin \left (d x + c\right ) - 2 \, A + 2 \, B\right )}}{a \sin \left (d x + c\right )^{3} + a \sin \left (d x + c\right )^{2} - a \sin \left (d x + c\right ) - a}}{16 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.13, size = 96, normalized size = 1.05 \[ \frac {\left (\frac {3\,A}{8}+\frac {B}{8}\right )\,{\sin \left (c+d\,x\right )}^2+\left (\frac {3\,A}{8}+\frac {B}{8}\right )\,\sin \left (c+d\,x\right )-\frac {A}{4}+\frac {B}{4}}{d\,\left (-a\,{\sin \left (c+d\,x\right )}^3-a\,{\sin \left (c+d\,x\right )}^2+a\,\sin \left (c+d\,x\right )+a\right )}+\frac {\mathrm {atanh}\left (\sin \left (c+d\,x\right )\right )\,\left (3\,A+B\right )}{8\,a\,d} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {\int \frac {A \sec ^{3}{\left (c + d x \right )}}{\sin {\left (c + d x \right )} + 1}\, dx + \int \frac {B \sin {\left (c + d x \right )} \sec ^{3}{\left (c + d x \right )}}{\sin {\left (c + d x \right )} + 1}\, dx}{a} \]
Verification of antiderivative is not currently implemented for this CAS.
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